MySQL：选择值最接近但大于给定值的行

Question

Okay, I'm struggling here. I have a MySQL table of unsorted values that is structured about like this:

ID     Size
-----  -----
1      12
2      10
3      1
4      0
5      8
6      9
7      6
8      2
9      9
10     4

What I'd like to do is given a size (eg size = 5) extract the next bigger rows (and the next smaller eventually).

I've tried:

SELECT * FROM Table WHERE Size > 5 ORDER BY Size DESC LIMIT 2

But that gives me:

ID     Size
-----  -----
1      12
2      10

but what I want is

ID     Size
-----  -----
7      6
5      8

Any help would be appreciated. I'm using PHP to access the table if that makes a difference. Thanks!

Answer 1

You are using DESC that fetching result in descending . you should use ASC that will fetch results in ascending.

Example-

SELECT * FROM Table WHERE Size > 5 ORDER BY Size ASC LIMIT 2

EDITED

You need to first fetch in descending order then you need to again order by ascending.

Example-

  SELECT * FROM
    (SELECT * FROM Table WHERE Size > 5 ORDER BY Size DESC ) AS r
ORDER BY r.Size ASC LIMIT 2

Answer 2

You could select the rows having size greater 5 as a sub-query and select first two rows from the result set of the sub-query.

Query

select t.* from(
  select * from your_table_name
  where size > 5
)t
order by t.size asc limit 2;

SQL Fiddle demo

Answer 3

您应该在ORDER BY子句中使用ASC，而不是DESC