[英]python recursion dir return NONE
1.recursion filesList in dir,if found the file then return the file path 1.递归文件在目录中列出,如果找到文件则返回文件路径
2.print value is true. 2.print值为true。 but always return NONE
但总是返回NONE
def getFilePath(filepath,fileName):
files = os.listdir(filepath)
for fi in files:
fi_d = os.path.join(filepath, fi)
if os.path.isdir(fi_d):
getFilePath(fi_d, fileName)
else :
if fi_d.find(fileName) == -1:
continue
else:
print fi_d
return fi_d
I think you should return at the end of the function only, otherwise python returns None 我认为您应该只在函数结尾处返回,否则python返回None
Also, need to capture the recursive return 另外,需要捕获递归收益
def getFilePath(filepath,fileName):
for fi in os.listdir(filepath):
fi_d = os.path.join(filepath, fi)
if os.path.isdir(fi_d):
fi_d = getFilePath(fi_d, fileName)
else :
if fi_d.find(fileName) == -1:
continue
else:
print fi_d
return fi_d
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