g ++-警告：扩展的初始化程序列表仅在-std = c ++ 11或-std = gnu ++ 11中可用

Question

I've following program.

#include <iostream>
#include <string>

int main() {
    int i {0};
    std::string str {"Hello World"};
    std::cout << i << " : " << str << std::endl;
    return 0;
}

When I compile this with g++ I got following error. I'm using g++ 5.4. g++ (Ubuntu 5.4.0-6ubuntu1~16.04.4) 5.4.0 20160609

warning: extended initializer lists only available with -std=c++11 or -std=gnu++11

I want to know what is the standard way to compile program in g++ using std::C++14 with necessary flags.

Thanks in Advance.

Update:

I've done it with following: g++ ./ex01.cpp -o ex01.out -std=c++14 -Wall -o2

Answer 1

用标志编译：

-std=c++14