简体   繁体   English

php下拉选择值

[英]php dropdown selected value

I'm having an edit form and within a dropdown box with movie-titles. 我有一个编辑表单,并且在带有电影标题的下拉框中。 One of them should be selected though, so say DVD_id: 100. How do I make this work in the code below? 但是,应该选择其中之一,例如DVD_id:100。如何在下面的代码中完成这项工作?

        <div class="form-group">
        <label for="Site name" class="col-md-4 control-label">DVD Title</label>
        <?php
        $query = "Select DISTINCT dvd.dvdname, dvd.dvd_id, FROM DVD where ORDER BY dvd.dvdname";
        $result = mysql_query($query) or die ("Couldn�t execute query.");?>
        <div class="col-md-8">
            <select id="box" name="dvdtitlefield" class="selectpicker form-control" multiple title="Choose one of the following..." >
                <?php
                while ($row = mysql_fetch_assoc($result))
                {
                    extract($row);
                    echo '<option value="'. $dvd_id .'">'. $dvdname .'</option>';
                }?>
            </select>
        </div>
    </div>

use the selected attribute of the option tag to make any option by default selected 使用选项标签的selected属性默认情况下使任何选项处于选中状态

<select>
<option value="tiger">tiger</option>
<option value="lion">lion</option>
<option value="zebra">zebra</option>
<option value="cat" selected>cat</option>
</select>

In your code you can just check which option you want to be selected by default and apply an if condition for it 在您的代码中,您可以只检查默认情况下要选择的选项,并为其应用if条件

example

<div class="form-group">
    <label for="Site name" class="col-md-4 control-label">DVD Title</label>
    <?php
    $query = "Select DISTINCT dvd.dvdname, dvd.dvd_id, FROM DVD where ORDER BY dvd.dvdname";
    $result = mysql_query($query) or die ("Couldn�t execute query.");?>
    <div class="col-md-8">
        <select id="box" name="dvdtitlefield" class="selectpicker form-control" multiple title="Choose one of the following..." >
            <?php
            while ($row = mysql_fetch_assoc($result))
            {
                extract($row);
                if($dvd_id==100)
                {
                echo '<option value="'. $dvd_id .'" selected>'. $dvdname .'</option>';
                }
                else
                {
                echo '<option value="'. $dvd_id .'">'. $dvdname .'</option>';
                }
            }?>
        </select>
    </div>
</div>

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM