[英]My C++ program cannot open named pipe
I am trying to run C++ application that works perfectly on Mac OS under Ubuntu. 我正在尝试运行在Ubuntu下的Mac OS上完美运行的C ++应用程序。 The problem is due to failure in opening a named pipe.
问题是由于无法打开命名管道。
I used mkfifo
as follows: 我按以下方式使用了
mkfifo
:
pipe_name_ = std::string("/tmp/myfifo");
if (mkfifo(pipe_name_.c_str(), 0666) < 0) {
error_print("Cannot create a named pipe\n");
return -1;
}
if ((fd_ = open(pipe_name_.c_str(), O_RDONLY | O_CREAT, 0666)) < 0) {
error_print("Cannot open file description named %s %s\n",
pipe_name_.c_str(), strerror(errno));
return -1;
}
However, this prints into screen the bellow message that is for open()
: 但是,这会在屏幕上显示
open()
以下消息:
Cannot open file description named /tmp/myfifo Invalid argument
My permissions status is as bellow: 我的权限状态如下:
$ls -la /tmp/myfifo
prw-r----- 1 hamidb nonconf 0 Jun 20 13:35 /tmp/myfifo
$umask
0027
I am wondering why it was working fine on Mac OS and not on Linux. 我想知道为什么它在Mac OS而不是Linux上能正常工作。
I believe that you have the wrong flags for open
as you are not creating the file. 我认为您没有
open
文件的错误标志,因为您没有创建文件。
It should be 它应该是
open(pipe_name_.c_str(), O_RDONLY)
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