将列表的字符串表示形式转换为列表

Question

list_string = "[1,3,4,6]"

I tried list_string[1:-1] but it is giving 1,3,4,6 . I also tried list_string.split(',') but again the brackets will be appended to first and last element ie '[1' , '3' , '4' , '6]'

I can iterate over all the items and remove brackets from 1st and last element. But what is the best and simple way to do this?

Answer 1

Assuming your string is a simple list/dict/combination of lists and dicts, you can use one of the two packages mentioned below, listed in order of preference.

json

>>> import json
>>> json.loads('[1, 2, 3]')
[1, 2, 3]

This is definitely the preferred method if you are parsing raw json strings.

---

ast.literal_eval

>>> import ast
>>> ast.literal_eval('[1, 2, 3]')
[1, 2, 3]

ast.literal_eval will safely evaluate an expression node or a string containing a Python literal or container display. The string or node provided may only consist of the following Python literal structures: strings, bytes, numbers, tuples, lists, dicts, sets, booleans, None, bytes and sets.

Also json.loads is significantly faster than ast.literal_eval . Use this ONLY IF you cannot use the json module first.

---

yaml

In some cases, you can also use the pyYAML library (you'll need to use PyPi to install it first).

>>> import yaml
>>> yaml.safe_load('[1, 2, 3]')
[1, 3, 4, 6]