While循环在Python中不起作用

Question

The while loop is not working properly. The again variable will dictate whether or not the while loop will be executed again. If again = 1, then the while loop will be executed and the program will run again. If again =0, then it will not.

For some reason, again=1 always, so no matter what, while loop is always being executed. Does anyone notice an error in the code?

 score = 0
 loops = 0
 again = 1
 while (again != 0):
    import random
    real = random.randint(1,9)
    fake1 = random.randint(1,9)
    fake2 = random.randint(1,9)
    comb = random.randint(1,9)
    rep = 0
    guess = 0

    if (comb == 1 or comb == 2 or comb == 3):
        print(real, fake1, fake2)
        loops += 1
        guess = int(input("Choose between these numbers"))
        if (guess == real):
            score += 1
            print ("Congrats!")
        else:
            print ("Wrong, better luck next time!")
    if (comb == 4 or comb == 5 or comb == 6):
        print (fake1, fake2, real)
        loops += 1
        guess = int(input("Choose between these numbers"))
        if (guess == real):
            score += 1
            print ("Congrats!")
        else:
            print ("Wrong, better luck next time!")

    if (comb == 7 or comb == 8 or comb == 9):
        print (fake2, real, fake1)
        loops += 1
        guess = int(input("Choose between these numbers"))
        if (guess == real):
            score += 1
            print ("Congrats!")
        else:
            print ("Wrong, better luck next time!")
    again == int(input("Do you wanna go again?"))
    print(again)

Answer 1

You use a comparison operator while assigning a value into variable called again :

again == int(input("Do you wanna go again?"))

You must delete one of the equals signs:

again = int(input("Do you wanna go again?"))

Answer 2

again == int(input("Do you wanna go again?"))

This is not going to do what you think, because == means it is checking if this statement is true. You want to have a single =.