我想在JavaScript中使用两个属性布尔值和Int对对象数组进行排序

Question

I want to sort an array of objects in JavaScript with Two properties Boolean value and Int value.I want Output like this :

{
    first_name: 'sumeet',
    last_name: 'Prentice',
    offerApplicable: 'TRUE',
    price: 40
}, {
    first_name: 'Pirate',
    last_name: 'Prentice',
    offerApplicable: 'TRUE',
    price: 50
}, {
    first_name: 'Lazslo',
    last_name: 'Jamf',
    offerApplicable: 'TRUE',
    price: 60
}, {
    first_name: 'jitendra',
    last_name: 'Prentice',
    offerApplicable: 'TRUE',
    price: 101
}

All object with true values are first also sorted with price and then all object having boolean value as false. i am able to sort them by boolean value but i want to sort them by price as well.

i have tried this

var objs = [ 
    { first_name: 'Lazslo', last_name: 'Jamf'   ,offerApplicable: 'TRUE' ,price: 60 },
    { first_name: 'Pig',    last_name: 'Bodine'  , offerApplicable: 'FALSE' ,price: 100},
    { first_name: 'Pirate', last_name: 'Prentice' ,offerApplicable: 'TRUE' ,price: 50},
    { first_name: 'nithesh',    last_name: 'Bodine'  , offerApplicable: 'FALSE' ,price: 40},
    { first_name: 'sumeet', last_name: 'Prentice' ,offerApplicable: 'TRUE' ,price: 40},
    { first_name: 'mahesh',    last_name: 'Bodine'  , offerApplicable: 'FALSE' ,price: 40},
    { first_name: 'jitendra', last_name: 'Prentice' ,offerApplicable: 'TRUE' ,price: 101}
];
function compare(a,b) {
    var aConcat = a["offerApplicable"] + a["price"];
      var bConcat = b["offerApplicable"] + b["price"];
  if (aConcat < bConcat )
    return 1;
  if (aConcat > bConcat )
    return -1;
  return 0;

}

console.log(objs.sort(compare));

i am getting output like this

first_name : "Lazslo" last_name : "Jamf" offerApplicable : "TRUE" price : 60

:first_name : "Pirate" last_name : "Prentice" offerApplicable : "TRUE" price : 50

first_name : "sumeet" last_name : "Prentice" offerApplicable : "TRUE" price : 40

first_name : "jitendra" last_name : "Prentice" offerApplicable : "TRUE" price : 101

first_name : "nithesh" last_name : "Bodine" offerApplicable : "FALSE" price : 40

first_name : "mahesh" last_name : "Bodine" offerApplicable : "FALSE" price : 40

first_name : "Pig" last_name : "Bodine" offerApplicable : "FALSE" price : 100

any help thanx in advance.

Answer 1

Just do it in little more steps.

First, get all true and false components in different arrays.

smth like this

const trueEntities = defaultArray.filter(e => e.offerApplicable === 'TRUE');
const falseEntities = defaultArray.filter(e => e.offerApplicable === 'FALSE');

then sort this arrays by price

const sortedByPriceTrue = trueEntities.sort((a, b) => a.price - b.price);
const sortedByPriceFalse =  falseEntities.sort((a, b) => a.price - b.price);

and then simply return/use in variable concated arrays

return sortedByPriceTrue.concat(sortedbyPriceFalse);

i know this solution maybe slower then one operation, but much more readable

ps edited, first solution didn't work as well

Answer 2

objs.sort(function (a, b) {
    return (a.price - b.price);
});

objs.sort(function (a, b) {
    var price1 = (a.offerApplicable === 'TRUE');
    var price2 = (b.offerApplicable === 'TRUE');
    return price2 - price1;
});

First, we sort the values by price & then, sort the value by offerApplicable field.

Combined Solution:

objs.sort(function (a, b) {
    var price1 = (a.offerApplicable === 'TRUE');
    var price2 = (b.offerApplicable === 'TRUE');
    return price2 - price1 || a.price - b.price;
});

Answer 3

You could chain the criteria for the rewturn value of the sort function of Array#sort .

The first part

(b.offerApplicable === 'TRUE') - (a.offerApplicable === 'TRUE')

performes a check if the value of offerApplicable is 'TRUE' . A comparison with true moves the item to the bottom, therfore we need to switch the check with a and b .

The second part

a.price - b.price

is only evaluated if the previous delta is zero, then the delta of price is returned.

 var array = [{ first_name: 'Lazslo', last_name: 'Jamf', offerApplicable: 'TRUE', price: 60 }, { first_name: 'Pig', last_name: 'Bodine', offerApplicable: 'FALSE', price: 100 }, { first_name: 'Pirate', last_name: 'Prentice', offerApplicable: 'TRUE', price: 50 }, { first_name: 'nithesh', last_name: 'Bodine', offerApplicable: 'FALSE', price: 40 }, { first_name: 'sumeet', last_name: 'Prentice', offerApplicable: 'TRUE', price: 40 }, { first_name: 'mahesh', last_name: 'Bodine', offerApplicable: 'FALSE', price: 40 }, { first_name: 'jitendra', last_name: 'Prentice', offerApplicable: 'TRUE', price: 101 }]; array.sort(function (a, b) { return (b.offerApplicable === 'TRUE') - (a.offerApplicable === 'TRUE') || a.price - b.price; }); console.log(result); 

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