如果我使用re.findall如何注册以便不分开

Question

I need to extract the numbers from this string :

str="((8,52),(30,52),2,0.5)"

if i used : re.findall('\\d+',str) i well get :

['20', '48', '48', '48', '2', '0', '5']

There is a problem with 0.5

How do I get 0.5 together to get :

['20', '48', '48', '48', '2', '0.5']

Answer 1

re.findall("\\d+\\.\\d+|\\d+",str)

正则表达式中的第一组将找到小数点两侧的数字，第二组将找到整数。

Answer 2

Use a numeric parse standard (?:\\d+(?:\\.\\d*)?|\\.\\d+)
Covers all cases:

5
5.
5.1
.1

Answer 3

re.findall(r'\d+\.?\d*',str)

输出：

['8', '52', '30', '52', '2', '0.5']