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如何从派生类中只获取基类属性?

[英]How to get only base class properties from derived class?

My code is like this 我的代码是这样的

public class BaseClass
{
    public string Field1 { get; set; }
}

public class DerivedClass: BaseClass
{
    public string Field2 { get; set; }
}

var obj = new DerivedClass { Field1 = "aaa", Field2 = "bbb" };

I have to serialize obj but I only need the BaseClass properties since DerivedClass properties are "additional info" which is added after deserialization. 我必须序列化obj但我只需要BaseClass属性,因为DerivedClass属性是反序列化后添加的“附加信息”。

How can I get them? 我怎么能得到它们? (I can't use [JSonIgnore] decorator because I have to send DerivedClass objects over websocket and I'll lose informations) (我不能使用[JSonIgnore]装饰器,因为我必须通过websocket发送DerivedClass对象,我将丢失信息)

You may define a custom contract resolver which would filter out all DerivedClass properties: 您可以定义一个自定义合约解析程序,它将过滤掉所有DerivedClass属性:

public class NoDerivedContractResolver : DefaultContractResolver
{
    protected override JsonProperty CreateProperty(MemberInfo member, MemberSerialization memberSerialization)
    {
        JsonProperty property = base.CreateProperty(member, memberSerialization);
        property.ShouldSerialize = _ => property.DeclaringType != typeof(DerivedClass);
        return property;
    }
}

// .................

var obj = new DerivedClass { Field1 = "aaa", Field2 = "bbb" };
var json = JsonConvert.SerializeObject(obj, new JsonSerializerSettings { 
    ContractResolver = new NoDerivedContractResolver() 
});
Console.WriteLine(json);

// Output:
//    {"Field1":"aaa"}

Demo: https://dotnetfiddle.net/Qailvp 演示: https//dotnetfiddle.net/Qailvp

You could provide your BaseClass with a constructor that takes a BaseClass as parameter und takes necessary information. 您可以为BaseClass提供一个构造函数,该构造函数将BaseClass作为参数并获取必要的信息。 This way you could create a new object and serialize it: 这样您就可以创建一个新对象并将其序列化:

public class BaseClass
{
    public string Field1 { get; set; }

    public BaseClass(){ }
    public BaseClass(BaseClass dc)
    {
        this.Field1 = dc.Field1;
    }
}

public class DerivedClass : BaseClass
{
    public string Field2 { get; set; }
}

Calling it like this: 这样称呼它:

var obj = new DerivedClass { Field1 = "aaa", Field2 = "bbb" };

BaseClass obj_base = new BaseClass(obj);

Can't you map a third class that contain all the data to serialise like this: 你不能映射包含所有数据序列化的第三个类,如下所示:

public class BaseClass
{
    public string Field1 { get; set; }
}

public class DerivedClass: BaseClass
{
    public string Field2 { get; set; }
}

public class BaseClassDTO{
    public string Field1 { get; set; }
    public BaseClassDTO(BaseClass baseClass){
        this.Field1 = baseClass.Field1;
    }
}

Some have propose ( https://github.com/quozd/awesome-dotnet#object-to-object-mapping ). 有人建议( https://github.com/quozd/awesome-dotnet#object-to-object-mapping )。 But i fear configuration will be complex for your need. 但我担心配置会因您的需要而变得复杂。

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