[英]NosuchMethod in dart for JSON.decode
Im trying to parse JSON from a file in dart. 我正在尝试从dart文件中解析JSON。 I've managed to read the file and print it, but when I try to convert it to JSON, it throws and error. 我设法读取并打印了文件,但是当我尝试将其转换为JSON时,它将引发错误。
file.dart: file.dart:
import 'dart:convert' as JSON;
import 'dart:io';
main() {
final jsonAsString = new File('./text.json').readAsString().then(print); //Successful printing of json
final json = JSON.decode(jsonAsString);
print('$json');
}
Error: 错误:
Unhandled exception:
NoSuchMethodError: No top-level method 'JSON.decode' declared.
Receiver: top-level
Tried calling: JSON.decode(Instance of '_Future')
#0 NoSuchMethodError._throwNew (dart:core-patch/errors_patch.dart:196)
#1 main (file:///Users/ninanjohn/Trials/dartTrials/stubVerifier.dart:7:15)
#2 _startIsolate.<anonymous closure> (dart:isolate-patch/isolate_patch.dart:265)
#3 _RawReceivePortImpl._handleMessage (dart:isolate-patch/isolate_patch.dart:151)
What am I missing or doing wrong here? 我在这里想念或做错了什么?
Firstly, when importing the dart:convert
library you are giving it an alias called JSON
. 首先,在导入dart:convert
库时,您为它提供了一个名为JSON
的别名。 Which means you would have to use it like; 这意味着您必须像这样使用它;
JSON.JSON.decode(jsonString);
I think you want to use show
instead of as
. 我认为您想使用show
而不是as
。 See this SO question for more details. 见这为更多的细节,以便问题。
The other issue is this line; 另一个问题是这条线。
final jsonAsString = new File('./text.json').readAsString().then(print);
You're not actually assigning a String
to that variable because because the .then()
method is returning a Future
. 您实际上并未将String
分配给该变量,因为.then()
方法将返回Future
。
Either read the file synchronously; 要么同步读取文件;要么同步读取文件。
final jsonAsString = new File('./text.json').readAsStringSync();
print(jsonAsString);
final json = JSON.decode(jsonAsString);
print('$json');
or change it to... 或将其更改为...
new File('./text.json').readAsString().then((String jsonAsString) {
print(jsonAsString);
final json = JSON.decode(jsonAsString);
print('$json');
});
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