[英]Overload subscript operator for base's member
#include <iostream>
#include <string.h> // strlen, strcpy
Here we have the Base class with a non-default ctor, a getter for name and its destructor. 在这里,我们有一个带有非默认ctor的Base类,一个用于名称的getter及其析构函数。
class Base {
char *name_;
public:
Base(const char* str)
: name_{new char[strlen(str)]}
{
strcpy(name_,str);
}
char * name() const
{
return name_;
}
virtual ~Base()
{
delete [] name_;
}
};
Derived class inherits from Base publicly and has its own non-default ctor. 派生类公开继承自Base,并且具有自己的非默认ctor。
class Derived : public Base {
public:
Derived(const char* str)
: Base(str){}
};
My question is how do I make the last line of code in main to work? 我的问题是如何使main中的最后一行代码起作用?
int main()
{
char d1name[] {"d1"};
Derived d1(d1name);
std::cout << d1.name() << std::endl;
d1.name[0] = 'D';
}
My question is how do I make the last line of code in main to work? 我的问题是如何使main中的最后一行代码起作用?
Just add parenthesis to call the getter 只需添加括号即可调用getter
d1.name()[0] = 'D';
// ^^
But in general that's a not so good idea. 但是总的来说,这不是一个好主意。 You could make the char
array in your base class public
then, or even better use a std::string
at all. 然后,您可以将基类中的char
数组public
,甚至更好地使用std::string
。
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