如果没有找到记录，SQL select 返回 0，否则返回值

Question

I am now using Microsoft SQL, my code is:

   SELECT TOP 1 
   [avail]
   FROM [table1]
   where [name] = 'abc'
   order by [datetime] desc

I hope when [avail] exists, return the value of [avail], if not exists, return 0 or "Not Found"

Thanks!

Answer 1

You can use this

SELECT ISNULL(( SELECT TOP 1 
   [avail]
   FROM [table1]
   where [name] = 'abc'
   order by [datetime] desc), 0) AS [avail]

Answer 2

You can do in two ways:

Use IF EXISTS way:

IF EXISTS (SELECT TOP 1 [avail] FROM [table1] WHERE [name] = 'abc' ORDER BY [datetime] DESC)
    SELECT TOP 1 [avail] FROM [table1] WHERE [name] = 'abc' ORDER BY [datetime] DESC
ELSE 
    SELECT 0 AS [avail]

or store the avail value into a variable and process, the only risk in this way is if the top 1 avail is returns empty value, then you will get the result as zero.

DECLARE @Avail AS VARCHAR(100) = ''; -- varchar of the `avail` data size

SELECT TOP 1 @Avail = [avail] FROM [table1] WHERE [name] = 'abc' ORDER BY [datetime] DESC;

IF @Avail = ''
    SELECT 0 AS [avail]
ELSE 
    SELECT @Avail AS [avail]

Answer 3

Try to use COALESCE. It selects the data from the first argument that has a nonnull value. If avail is not null, return [avale], otherwise return "Not Found"

SELECT COALESCE(avail, 'Not Found')
FROM table1
WHERE name = 'abc'
ORDER BY datetime desc

You can read about COALESCE in https://docs.microsoft.com/en-us/sql/t-sql/language-elements/coalesce-transact-sql

Answer 4

If its top 1 you want or remove top command

 SELECT TOP 1 
   isnull([avail],'0')
   FROM [table1]
   where [name] = 'abc'
   order by [datetime] desc