Spring启动运行多个应用程序

Question

I have one project with multiple modules, every module itself is spring boot application. I need to run all this applications with one command(using .bat for windows OR one maven run), how can I do it?

Project structure looking like this:

/base-app
  /auth-service
     /pom.xml - child pom
  /eureka-service
     /pom.xml
  /zuul-service
     /pom.xml
pom.xml - main pom

I can't understand at all how to do it with maven. But I tried to do it with .bat file like this:

call mvn -f eureka-service/pom.xml spring-boot:run
call mvn -f zuul/pom.xml spring-boot:run

First "call" worked fine, but second one was ignored.
I need this to fast start all my services.

Answer 1

This smells monolith all over. I can't really justify use of a parent pom, in a microservice world (arguable). This is just my honest opinion, your scenario might be totally different.

That being said, I believe, each of the child projects (auth-service,euraka and zuul) are creating it's own artifacts (jars). If yes, you can just do java -jar on each of that in your .bat or shell commands.

Answer 2

If you run each of your services in a separate Docker container, Docker Compose will do what you're looking for and bring up all the services in their containers in one command with:

docker-compose up

See https://docs.docker.com/compose/