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使用GSON不解析字段,只保留json原始字符串

[英]Using GSON do not parse a field, only keep it with the json raw string

Using GSON in Java is there any annotation where I can indicate a field that it should keep it as a raw string even though it is an object. 在Java中使用GSON是否有任何注释,我可以指示一个字段,即使它是一个对象,它应该将它保持为原始字符串。 ?

Or What would be the easiest way to achieve this? 或者最简单的方法是什么?

//This is the original
    @SerializedName("perro")
    public Perro perro

//This is what I want to achieve 
    @SerializedName("perro")
    public String perro

So the result should be 
perro = "{"Users":[{"Name":"firulais","Raza":"beagle"},{"Name":"Spike","Value":"Terrier"}]}"

我发现这个工作的唯一方法是使用

public JsonElement perro;

Basically speaking, You need to create a custom gson TypeAdapter class and write the conversion login from Object to String yourself. 基本上,您需要创建一个自定义的gson TypeAdapter类,并自己编写从Object到String的转换登录。

Then annotate the field indicating what TypeAdapter to use in order to read/write it using gson. 然后注释该字段,指示要使用哪个TypeAdapter以使用gson读取/写入它。

More details in this blog post: Gson TypeAdapter Example 此博客文章中的更多详细信息: Gson TypeAdapter示例

Example: Prasing class object as a raw JSON string 示例:将类对象作为原始JSON字符串进行打包

public class StringTypeAdapter extends TypeAdapter<String> {

    @Override
    public void write(JsonWriter out, String value) throws IOException {
        try {
            JSONObject jsonObject = new JSONObject(value);
            out.beginObject();
            Iterator<String> iterator = jsonObject.keys();
            while (iterator.hasNext()) {
                String key = iterator.next();
                String keyValue = jsonObject.getString(key);
                out.name(key).value(keyValue);
            }
            out.endObject();
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

    @Override
    public String read(JsonReader in) throws IOException {
        in.beginObject();
        JSONObject jsonObject = new JSONObject();
        while (in.hasNext()) {
            final String name = in.nextName();
            final String value = in.nextString();
            try {
                jsonObject.put(name, value);
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }
        in.endObject();
        return jsonObject.toString();
    }
}

Using the TypeAdapter: 使用TypeAdapter:

@JsonAdapter(StringTypeAdapter.class)
private String someClass; // Lazy parsing this json

Based on @mrsegev's answer, here's a simpler version (in Kotlin) that works with arbitrary objects: 根据@ mrsegev的回答,这里有一个更简单的版本(在Kotlin中),适用于任意对象:

class RawJsonAdapter: TypeAdapter<String>() {
    override fun write(out: JsonWriter?, value: String?) {
        out?.jsonValue(value)
    }
    override fun read(reader: JsonReader?): String {
        return JsonParser().parse(reader).toString()
    }
}

This takes advantage of JsonWriter#jsonValue() which was added in https://github.com/google/gson/pull/667 这利用了https://github.com/google/gson/pull/667中添加的JsonWriter#jsonValue()

Usage: 用法:

@JsonAdapter(RawJsonAdapter::class)
val fieldName: String? = null

You should be able to use public JsonObject perro; 你应该能够使用public JsonObject perro;

You can then call gson.toJson(perro) to get the String value. 然后,您可以调用gson.toJson(perro)来获取String值。

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