如何从选择器中获取所有元素包含的属性的每个值？

Question

this is my first question and i hope it makes sense because i am quite a rookie at javascript/jquery.

So, i have a varying amount of elements with the custom attribute data-value=<?php echo $value ?>

Once the page has loaded I have some javascript $('[data-value]') to select all the elements on the page with the attribute 'data-value'. This returns an array with all the relevant elements. Then i tried getting the values with $('[data-value]').data('value') . Now, while this is returning the right result, it's only returning it for the first element it comes across. I tried iterating through the code with $('[data-value]')[num].data('value') where 'num' is between zero and the array length. This, sadly, didn't work.

So is there any way to grab all the values of a particular attribute that all the selected elements have?

Answer 1

To get the values of all the selected elements, you need to loop through the list and pick the value of those, like this:

var values = $("[data-value]").map(function(i, el) {
  return el.data('value');
});

console.log(values);

Hope that helps!

Answer 2

you can do something like this:

$('[data-value]').each(function(){
   console.log($(this).data('value'));
});

Answer 3

You can use the .each() method to iterate through your elements.

$('[data-value]').each(function() {
    console.log( $(this).data('value');
}

You can also use the for loop as you have tried, with a simple modification. When you do $('[data-value]')[num] , you actually get the native element, and not a jQuery object, so .data() is no longer available. To fix this, you can re-wrap the element in a jQuery object. $( $('[data-value]')[num] ).data('value')