使用JQ使用来自另一个JSON的值更新一个JSON文件值

Question

So I have two JSON files:

bosh.json:

{
  "key_pair_name": "my-aws-keypair",
  "ssh_private_key": "my-key-name",
  "trusted_certificates": "my-trusted-certs"
}

model.json:

{
  "trusted_certificates": "vault-supplied-value",
  "vm_password_type": "generate"
}

and I want to update the model.json file with the bosh.json file so it looks like this:

{
  "trusted_certificates": "my-trusted-certs",
  "vm_password_type": "generate"
}

I tried this:

jq --argfile bosh bosh.json '. += $bosh' model.json

but I get too many keys

{
  "trusted_certificates": "my-trusted-certs",
  "vm_password_type": "generate",
  "key_pair_name": "my-aws-keypair",
  "ssh_private_key": "my-key-name"
}

and

jq --argfile bosh bosh.json '. + $bosh' model.json

yeilds the same...

{
  "trusted_certificates": "my-trusted-certs",
  "vm_password_type": "generate",
  "key_pair_name": "my-aws-keypair",
  "ssh_private_key": "my-key-name"
}

while this

jq --argfile bosh bosh.json '. = $bosh' model.json

yields the incorrect keys...

{
  "key_pair_name": "my-aws-keypair",
  "ssh_private_key": "my-key-name",
  "trusted_certificates": "my-trusted-certs"
}

Does anyone have any ideas how to get the expected results using jq? by the way, I cannot use the value of the key for the updates, as i will have unexpected results in other permutations...

Answer 1

jq solution:

jq --argfile bosh bosh.json 'with_entries( 
         if $bosh[.key] then .value = $bosh[.key] else . end)' model.json

The output:

{
  "trusted_certificates": "my-trusted-certs",
  "vm_password_type": "generate"
}

---

• if $bosh[.key] then .value = $bosh[.key] else . end if $bosh[.key] then .value = $bosh[.key] else . end - update model 's value only for matched keys

Answer 2

The requirements are not completely clear, but here's the solution to one interpretation. This solution can easily be modified to match the other obvious interpretation.

Assuming the file bosh.jq contains the following jq program:

reduce keys[] as $k (.; if $bosh|has($k) then .[$k] = $bosh[$k] else . end)

then the command:

jq --argfile bosh bosh.json -f bosh.jq model.json

will in effect emit the edited version of model.json.

Using with_entries

If you prefer a reduce-free approach, consider:

with_entries(.key as $k | if $bosh|has($k) then .value = $bosh[$k] else . end )

Note that if $bosh|has($k) ... is NOT the same as if $bosh[$k] ... .