比较数组中的值与其他所有值

Question

I have an array like so:

$array = [['name'=> 'one'], ['name'=>'two'],['name'=> 'three'], ['name'=>'four']];

I want to compare/print every combination from that array:

one -> two one -> three ... two -> three two -> four

and so on...

I tried

<?php foreach ($compares as $k1 => $v1 ){
    echo $v1->id.'<br>';

    foreach ($compares2 as $k2 => $v2 ){
        if($k1 == $k2) echo $v2->id.'<br>';
    }
}

?>

Answer 1

I don't know if I understand your requirements correctly (I can modify it if you want). Have a look at this example:

<?php

$array = [
    ['name'=> 'one'], 
    ['name'=>'two'],
    ['name'=> 'three'], 
    ['name'=>'four']
];

for ($i = 0; $i < count($array)-1; $i++) {
    for ($j = $i+1; $j < count($array); $j++) {
        echo $array[$i]['name'] . ' > ';
        echo $array[$j]['name'] . '<br>';
    }
}

Answer 2

Pavels answer seem to be right, maybe you should check your values for duplicates?

<?php

$array = [['id'=> 'one'],['id'=>'two'],['id'=> 'three'],['id'=>'four']];

for ($i = 0; $i < count($array)-1; $i++) {
    for ($j = $i+1; $j < count($array); $j++) {
        echo $array[$i]['id'] . ' - ';
        echo $array[$j]['id'] . '<br>';
    }
} 

?>

OUTPUT:

one - two
one - three
one - four
two - three
two - four
three - four