PHP计算每天节省的文档总数

Question

I'm trying to get the total document saves per day. But i don't have any idea how. Here are the Columns along with their data in my Database.

report_id    doc_date   total_doc 
- 1          2017-06-06  1  
- 2          2017-06-23  1  
- 3          2017-06-14  1  
- 4          2017-06-12  1  
- 5          2017-06-16  1
- 6          2017-06-21  1
- 7          2017-06-14  1
- 9          2017-06-13  1
- 10         2017-06-21  1
- 11         2017-06-12  1
- 12         2017-06-18  1
- 13         2017-06-12  1
.....

Above, there are similar date, for example,

- 3          2017-06-14  1
- 7          2017-06-14  1 

I need a sql query which would calculate and show the total document saves per day. So for 14 of June 2017, the total would be 2. Any idea guys? FYI the total_doc is automatically equal to 1. Updated: And show the total document saves in that day.

Answer 1

Try this (set table_name to the name of your table):

SET @row_count = 0;
SELECT (@row_count:=@row_count+1) AS totalSaves FROM table_name WHERE doc_date='2017-06-14'

The first line defines a variable, row_count , and sets it to 0 .

The second line goes through the database, finds all rows where the date is 2017-06-14 , and for each one increments row_count .

Then, we SELECT the final number stored in row_count as a single row in a column labeled as totalSaves .

Set table_name to the name of your table

Answer 2

SELECT doc_date, sum(total_doc) AS total 
FROM table_name
GROUP BY doc_date

Change table_name with your table name.

If you just want show 1 date :

SELECT doc_date, sum(total_doc) AS total 
FROM table_name
WHERE doc_date = '2017-06-14'
GROUP BY doc_date

Answer 3

SELECT 
    doc_date,
    count(doc_date) AS saves
FROM documents
GROUP BY doc_date
ORDER BY doc_date ASC;

OR

SELECT
    doc_date,
    sum(total_doc) AS saves
FROM documents
GROUP BY doc_date
ORDER BY doc_date ASC;

Notices:

1) If you are using the first option, then you can remove the column total_doc . That would also be my advice. You have a good mysql format of the date values in the doc_date column, so you can make solid operations on it.

2) You can sort the records in a descending order by doc_date , if you wish.

3) Don't forget to alias (like I did with AS saves ) the columns when using functions like count or sum . Because then you can use a HAVING filter also. So something like this - all documents with more than one save per day:

SELECT 
    doc_date,
    count(doc_date) AS saves
FROM documents
GROUP BY doc_date
HAVING saves > 1
ORDER BY doc_date ASC;

And then you can also filter by only one saved document on a specified day:

SELECT 
    doc_date,
    count(doc_date) AS saves
FROM documents
WHERE doc_date = "2017-06-12"
GROUP BY doc_date
HAVING saves > 1
ORDER BY doc_date ASC;

4) Or you can also just ignore HAVING and doc_date if you wish. That would give you the documents saved on a specified day.

SELECT count(doc_date) AS saves
FROM documents
WHERE doc_date = "2017-06-12"
GROUP BY doc_date
ORDER BY doc_date ASC;