[英]PHP, SQL Insert no works
i would like to know why i am not able to insert new data to my Database. 我想知道为什么我不能将新数据插入数据库。 in vardump i get good result but nothing is added to my database 在vardump中,我得到了很好的结果,但是没有任何内容被添加到我的数据库中
Database : c_id = AutoInc. 数据库:c_id = AutoInc。 | | a_id | a_id | u_id | u_id | c_head | c_head | c_content | c_content | c_date =TIMESTAMP c_date =时间戳
if (isset($_POST['c_submit'])) {
$sql_najdi_prihlaseneho_uzivatela = "SELECT * FROM users where u_name = '$_SESSION[username]'";
$vysledokHladania = mysqli_query($connect_to_db, $sql_najdi_prihlaseneho_uzivatela);
if (mysqli_num_rows($vysledokHladania) == 1) {
while ($db_data_prihlaseneho_uzivatela = mysqli_fetch_assoc($vysledokHladania)) {
$sql_vloz_komentar = "INSERT INTO comments (a_id, u_id, c_head, c_content, c_date) VALUES ($_GET[a_id], $db_data_prihlaseneho_uzivatela[u_id], $_POST[c_hlavicka], $_POST[c_obsah], 'NOW()')";
mysqli_query($connect_to_db, $sql_vloz_komentar);
}
}
}
You can use date('Ymd h:i:s')
to store current date time in our DB by PHP code and in your query you just missed to put '' in array index. 您可以使用date('Ymd h:i:s')
通过PHP代码将当前日期时间存储在我们的数据库中,而在查询中您只是想将''放在数组索引中。
Try this one 试试这个
if (isset($_POST['c_submit'])) {
$date=date('Y-m-d h:i:s');
$sql_najdi_prihlaseneho_uzivatela = "SELECT * FROM users where u_name = '".$_SESSION['username']."'";
$vysledokHladania = mysqli_query($connect_to_db, $sql_najdi_prihlaseneho_uzivatela);
if (mysqli_num_rows($vysledokHladania) == 1) {
while ($db_data_prihlaseneho_uzivatela = mysqli_fetch_assoc($vysledokHladania)) {
$sql_vloz_komentar = "INSERT INTO comments (a_id, u_id, c_head, c_content, c_date) VALUES
(".$_GET['a_id'].",".$db_data_prihlaseneho_uzivatela['u_id']." ,".$_POST['c_hlavicka']." ,".$_POST['c_obsah']." ,$date)";
mysqli_query($connect_to_db, $sql_vloz_komentar);
}
}
}
I thing it will help you. 我认为这会对您有所帮助。
do you escape the varchar character ? 你能逃脱varchar字符吗? Other posible error is the date format in database. 其他可能的错误是数据库中的日期格式。 Post echo $sql_vloz_komentar
for view the insert statement and the structure of table 发表echo $sql_vloz_komentar
以查看插入语句和表的结构
if (isset($_POST['c_submit'])) {
$sql_najdi_prihlaseneho_uzivatela = "SELECT * FROM users where u_name = '$_SESSION[username]'";
$vysledokHladania = mysqli_query($connect_to_db, $sql_najdi_prihlaseneho_uzivatela);
if (mysqli_num_rows($vysledokHladania) == 1) {
while ($db_data_prihlaseneho_uzivatela = mysqli_fetch_assoc($vysledokHladania)) {
$sql_vloz_komentar = "INSERT INTO comments (a_id, u_id, c_head, c_content, c_date) VALUES ($_GET[a_id], $db_data_prihlaseneho_uzivatela[u_id], '$_POST[c_hlavicka]', '$_POST[c_obsah]', 'NOW()')";
mysqli_query($connect_to_db, $sql_vloz_komentar);
}
}
}
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