[英]SQL Alchemy/ Flask / WTF Forms set a default value for a queryselectfield
I want to set a default value for my queryselectfield. 我想为我的queryselectfield设置默认值。 My code looks like this:
我的代码如下所示:
Template: 模板:
{% import "bootstrap/utils.html" as utils %}
{% import "bootstrap/wtf.html" as wtf %}
{% extends "base.html" %}
{% block title %}Request{% endblock %}
{% block body %}
<div class="content-section">
...
{{ form.country(class_="selectformfield") }
...
Route: 路线:
@requests.route('/request/add', methods=['GET', 'POST'])
@login_required
def add_request():
check_admin()
add_request = True
form = RequestForm()
if form.validate_on_submit():
...
Country = form.hostname.data
...
request = Request(...country=country, ...)
try:
# add request to the database
db.session.add(request)
db.session.commit()
flash('You have successfully added a new request.')
except:
# in case request name already exists
flash('Error: request already exists.')
# redirect to the request page
return redirect(url_for('requests.show_request', id=request.id))
# load request template
return render_template('requests/add_request.html', add_request=add_request,
form=form, title='Add new Request')
Form: 形成:
class RequestForm(FlaskForm):
...
country = QuerySelectField(query_factory=lambda: Country.query.all(), get_label="name")
...
I already tried it like this, but it didn't work. 我已经这样尝试过了,但是没有用。
default_country = query_factory=lambda: Country.query.filter(Country.id == '1')
country = QuerySelectField(query_factory=lambda: Country.query.all(), get_label="name", default=default_country)
SQLAlchemy/WTForms: set default selected value for QuerySelectField I also already read this post here with a simmilar problem, but the solution doesn't work for me. SQLAlchemy / WTForms:设置QuerySelectField的默认选择值我也已经在这里阅读了类似的文章,但是该解决方案对我不起作用。 Can annyone help me?
能帮助我吗?
Try this: 尝试这个:
default=lambda: Country.query.filter(Country.id == '1').one_or_none())
here the complete code of your field definition: 这里是您的字段定义的完整代码:
country = QuerySelectField(query_factory=lambda: Country.query.all(), get_label="name", default=lambda: Country.query.filter(Country.id == '1').one_or_none())
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.