[英]How would I go about getting info from a list of link then dump them into a JSON object?
New to Python and BeautifulSoup. Python和BeautifulSoup的新功能。 Any help is highly appreciated
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I have an idea of how to build one list of a companies info, but that's after clicking on one link. 我对如何建立的公司信息一个列表的想法,但点击一个链接后的。
import requests
from bs4 import BeautifulSoup
url = "http://data-interview.enigmalabs.org/companies/"
r = requests.get(url)
soup = BeautifulSoup(r.content)
links = soup.find_all("a")
link_list = []
for link in links:
print link.get("href"), link.text
g_data = soup.find_all("div",{"class": "table-responsive"})
for link in links:
print link_list.append(link)
Can anyone give an idea of how to go about first scraping the links then building a JSON of all of the company listings data for the site? 谁能提出一个想法,首先去抓取链接,然后为站点的所有公司列表数据构建一个JSON?
I attached sample images for a better visualization as well. 我还附加了示例图像,以实现更好的可视化效果。
How would I scrape the site and build a JSON like my example below without having to click on each individual link? 我如何刮取网站并像下面的示例一样构建JSON,而不必单击每个单独的链接?
Example Expected Output: 预期输出示例:
all_listing = [ {"Dickens-Tillman":{'Company Detail':
{'Company Name': 'Dickens-Tillman',
'Address Line 1 ': '7147 Guilford Turnpike Suit816',
'Address Line 2 ': 'Suite 708',
'City': 'Connfurt',
'State': 'Iowa',
'Zipcode ': '22598',
'Phone': '00866539483',
'Company Website ': 'lockman.com',
'Company Description': 'enable robust paradigms'}}},
`{'"Klein-Powlowski" ':{'Company Detail':
{'Company Name': 'Klein-Powlowski',
'Address Line 1 ': '32746 Gaylord Harbors',
'Address Line 2 ': 'Suite 866',
'City': 'Lake Mario',
'State': 'Kentucky',
'Zipcode ': '45517',
'Phone': '1-299-479-5649',
'Company Website ': 'marquardt.biz',
'Company Description': 'monetize scalable paradigms'}}}]
print all_listing`
Here is my final solution to the question I asked. 这是我提出的问题的最终解决方案。
import bs4, urlparse, json, requests,csv
from os.path import basename as bn
links = []
data = {}
base = 'http://data-interview.enigmalabs.org/'
#Approach
#1. Each individual pages, collect the links
#2. Iterate over each link in a list
#3. Before moving on each the list for links if correct move on, if not review step 2 then 1
#4. Push correct data to a JSON file
def bs(r):
return bs4.BeautifulSoup(requests.get(urlparse.urljoin(base, r).encode()).content, 'html.parser').find('table')
for i in range(1,11):
print 'Collecting page %d' % i
links += [a['href'] for a in bs('companies?page=%d' % i).findAll('a')]
# Search a the given range of "a" on each page
# Now that I have collected all links into an list,iterate over each link
# All the info is within a html table, so search and collect all company info in data
for link in links:
print 'Processing %s' % link
name = bn(link)
data[name] = {}
for row in bs(link).findAll('tr'):
desc, cont = row.findAll('td')
data[name][desc.text.encode()] = cont.text.encode()
print json.dumps(data)
# Final step is to have all data formating
json_data = json.dumps(data, indent=4)
file = open("solution.json","w")
file.write(json_data)
file.close()
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