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对Servlet的AJAX调用不起作用

[英]AJAX call to servlet not working

I have a servlet that will insert form input fields into my database and it works when I set 我有一个Servlet,它将在我的数据库中插入表单输入字段,并且在设置时可以正常工作

<form action="CreateUserServlet">

but I wanted to try some form validation stuff and the ajax servlet call returns success but the data is not added to my database. 但是我想尝试一些表单验证的东西,并且ajax servlet调用返回成功,但是数据没有添加到我的数据库中。

servlet: Servlet:

protected void processRequest(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    response.setContentType("text/html;charset=UTF-8");
    String username = request.getParameter("usernameField");
    String password = request.getParameter("passwordField");

    if (MySqlCon.createUser(username, password)) {
        try (PrintWriter out = response.getWriter()) {
            out.println("<script type=\"text/javascript\">");
            out.println("alert('Account Successfully Created!');");
            out.println("</script>");
        }
    } else {
        try (PrintWriter out = response.getWriter()) {
            out.println("<script type=\"text/javascript\">");
            out.println("alert('Error in Creating Account!');");
            out.println("</script>");
        }
    }
}

html form html表格

<div class="collapse" id="createAcc">
                <div class="create-wrapper">
                    <form method="post" id="create-ajax">
                        <h3> Enter your details </h3>
                        <div class="row">
                            <div class="col-md-12"> 
                                <input type="text" name="usernameField" placeholder="choose username" id="createUsername"/>
                                <p class="hideMsg" id="createUserError">bad username, try again</p>
                            </div>
                        </div>
                        <div class="row">
                            <div class="col-md-12">
                                <input type="text" name="passwordField" placeholder="choose password" id="createPassword"/>
                                <p class="hideMsg" id="createPasswordError">bad password, try again</p>
                            </div>
                        </div>
                        <div class="row buttonRow">
                            <div class="col-md-12">
                                <input id="submitCreateAcc" type="submit" value="Create"/>
                                <p class="hideMsg" id="successMsg">Account created!</p>
                            </div>
                        </div>
                    </form>
                </div>
            </div>

the javascript: javascript:

$(document).ready(function () {
var createForm = $('#create-ajax');

$(createForm).submit(function (event) {
    event.preventDefault();

    var username = $('#createUsername').val();
    var password = $('#createPassword').val();

    if (username.length < 6) {
        $('#createUserError').removeClass('hideMsg').addClass('showMsg');
    } else {
        $('#createUserError').removeClass('showMsg').addClass('hideMsg');
    }
    if (password.length < 8) {
        $('#createPasswordError').removeClass('hideMsg').addClass('showMsg');
    } else {
        $('#createPasswordError').removeClass('showMsg').addClass('hideMsg');
    }

    if (username.length >= 6 && password.length >= 8) {
        $.ajax({
            url: 'CreateUserServlet',
            method: 'POST',
            success: function () {
                $('#successMsg').removeClass('hideMsg').addClass('showMsg');
            }
        });
    }
})
});

The sucessMsg is shown but the data did not get inserted. 显示了sucessMsg,但未插入数据。 Any help is appreciated, thanks 任何帮助表示赞赏,谢谢

You need to provide the data to submit with the post request, it does not get bound automatically. 您需要提供要与发布请求一起提交的数据,它不会自动绑定。

$.ajax({
  url: 'CreateUserServlet',
  method: 'POST',
  data: createForm.serialize(),
  success: function () {
    $('#successMsg').removeClass('hideMsg').addClass('showMsg');
  }
});

And returning an alert from the server makes no sense in this case. 在这种情况下,从服务器返回警报是没有意义的。 You should return back a JSON object with the value you want to display to the user. 您应该返回一个JSON对象,该对象具有要显示给用户的值。

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