正则表达式-捕获两个字符串之间的所有下划线

Question

In this string(this is not my code, just sample input)

var b_1 = goog.require('a_b_b');
console.log(b_1.b);

a_b_b should be renamed to abb , so all underscores inside a goog.require('...') statement should be renamed to a . .

I came up with this regex:

/goog\.require\('(?:[^_]*(_)[^_]*)*'\)/g

Explanation:

goog\.require\('   literal
(?:                non-capturing group
[^_]*              match anything except underscore
(_)                capture underscore
[^_]*              match anything except underscore
)                  end of non-capturing group
*                  there can be more than one underscore in a goog.require statement
'\)                literal

But this only captures the last underscore. How can I capture all underscores in a goog.require('...') statement?

I don't know if it's useful, but I'm replacing the underscores with javascript, so look behinds are not (natively) supported.

To be clear: I only want the underscores inside the goog.require('...') statement to be replaced, so the underscore in b_1 should not be replaced.

Answer 1

You can use this regex:

var result = str.replace(/goog\.require\('[^']+'\)/g, function (match) {
    return match.replace(/_/g, '.');
});

This first finds all occurrences that match the goog.require('str') form and replaces all occurrences of '_' with '.' .