用jquery和regex格式化正负十进制数

Question

I found this code below at jsfiddle that, in my shitty opinion, is very nice. But it doesn't format negative numbers, only positive. I tried to modify it but my regex knowledge wasn't enough. Could anyone help me modify this to format positive and negative numbers?

 $('#valor').keyup(function(){ var v = $(this).val(); v = v.replace(/\\D/g,''); v = v.replace(/(\\d{1,2})$/, ',$1'); v = v.replace(/(\\d)(?=(\\d{3})+(?!\\d))/g, '$1.'); v = v != '' ? 'R$ '+ v : ''; $(this).val(v); }); 

Answer 1

You could just check and see if the value is negative when you start, and add the sign back in at the end:

$('#valor').keyup(function(){
    let v = $(this).val();
    const neg = v.startsWith('-');

    v = v.replace(/[-\D]/g,'');
    v = v.replace(/(\d{1,2})$/, ',$1');
    v = v.replace(/(\d)(?=(\d{3})+(?!\d))/g, '$1.');

    v = v != ''?'$ '+v:'';
    if(neg) v = '-'.concat(v);  // prepend the dash

    $(this).val(v);
});

jsfiddle

---

EDIT: Here's a more "pure" regex solution:

$('#valor').keyup(function(){
    let v = $(this).val();

    v = v.replace(/[^-\d]/g, '');
    v = v.replace(/(\d{1,2})$/g, ',$1');
    v = v.replace(/(\d)(?=(\d{3})+(?!\d))/g, '$1.');

    v = v ? '$ ' + v : '';
    $(this).val(v);

});

jsfiddle

Basically, in the first replace statement, you add '-' to the set of characters to not get replaced, ie everything that isn't a digit or a dash will get replaced by '' in this new version.