如何用python制作x y线图？

Question

Hello I have the following dataframe:

df = [{'Column1': 1, 'Colunm2': 'A', 'Colunm3': 2}, 
      {'Column1': 2, 'Colunm2': 'A', 'Colunm3': 4},
      {'Column1': 3, 'Colunm2': 'A', 'Colunm3': 1},
      {'Column1': 1, 'Colunm2': 'B', 'Colunm3': 7},
      {'Column1': 2, 'Colunm2': 'B', 'Colunm3': 2},
      {'Column1': 3, 'Colunm2': 'B', 'Colunm3': 9}]

How can I make a XY plot between Column1 and Colunm3 but plotting two diffentent lines, one for values Colunm2 = 'A' and other for values Colunm2 ='B' ?

Answer 1

IIUC:

import pandas as pd
df1 = pd.DataFrame(df)
fig,ax = plt.subplots()
for i,g in df1.groupby('Colunm2'):
    g.plot('Column1','Colunm3',ax=ax,label=i)

Answer 2

As pointed out by @ScottBoston in his comment there is also sns.pointplot where the hue parameter is effectively a groupby.

import sns.apiponly as sns
sns.pointplot('Column1', 'Colunm3', data=DataFrame(df), hue='Colunm2')
plt.ylabel('Colunm3')

Answer 3

You can try this:

import matplotlib.pyplot as plt

df = [{'Column1': 1, 'Colunm2': 'A', 'Colunm3': 2},
      {'Column1': 2, 'Colunm2': 'A', 'Colunm3': 4},
      {'Column1': 3, 'Colunm2': 'A', 'Colunm3': 1},
      {'Column1': 1, 'Colunm2': 'B', 'Colunm3': 7},
      {'Column1': 2, 'Colunm2': 'B', 'Colunm3': 2},
      {'Column1': 3, 'Colunm2': 'B', 'Colunm3': 9}]

first = [(i["Column1"], i['Colunm3'])  for i in df if i['Colunm2'] == 'A']
second = [(i["Column1"], i['Colunm3']) for i in df if i['Colunm2'] == 'B']


plt.plot([a for a, b in first], [b for a, b in first])
plt.plot([a for a, b in second], [b for a, b in second])

plt.show()