我如何使用所有数字而不是python中的第一位对列表进行排序？

Question

sorted(users, key=attrgetter('user_id'), reverse=True)[:10]

This line is sorting the list of object based on first digit but i want all digit to consider during sort in python.

#!/usr/bin/python

import sys
from operator import attrgetter

class User:
    def __init__(self, x, y):
        self.name = x
        self.user_id = y

    def __repr__(self):
        return self.name + ":" + str(self.user_id)


users = []

for line in sys.stdin:
    data = line.strip().split('\t')
    users.append(User(data[0],data[-1]))


for user in users:
    print(user)

print('-----------')

for user in sorted(users, key=attrgetter('user_id'), reverse=True)[:10]:
    print(user)

Answer 1

Convert the strings to int and sorting them would help you sort using all the digits.

for line in sys.stdin:
    data = line.strip().split('\t')
    users.append(User(data[0],int(data[-1])))

Answer 2

If user_id is an integer, you should treat it as such by casting it to int. This will make the sort work as expected. Make one of these changes:

class User:
    def __init__(self, x, y):
        self.name = x
        self.user_id = int(y)

    def __repr__(self):
        return self.name + ":" + str(self.user_id)

or, alternatively,

users = []

for line in sys.stdin:
    data = line.strip().split('\t')
    users.append(User(data[0],int(data[-1])))