字符串中每个单词的频率

Question

I am writing some code which finds the frequency of every word in a given string using the strtok() and the strstr() functions. I don't know what is the problem with my code as no output is being displayed on the screen. Can anyone help me?I am new to C programming.

#include<stdio.h>
#include<string.h>
void main(){

  char s[2222];
  gets(s);
  char *t,*y=s;
  int count=0;
  t=strtok(s," ,.");

  while(t!=NULL)
  {
    count=0;
    while(y=strstr(y,t))
    {
      y++;
      count++;
    }
    printf("%s appeared %d times.\n",t,count);
    t=strtok(NULL," ,.");
  }
}

Answer 1

1. You cannot use strstr to search for words: the number of occurrence of "is" in "is this a test?" is two, not one.
2. You cannot use strtok two times; first time to search for first occurrence and second time for subsequent occurrences, instead of strstr : strtok is using a static variable (see the note in this page ).

[EDIT]

A begginner solution ( run it ):

#include<stdio.h>
#include<string.h>

#define MAXWORD 32
typedef struct
{
  char word[MAXWORD];
  int count;
} word_and_count_t;

#define MAXWORDCOUNT 1024
word_and_count_t table[MAXWORDCOUNT];

int table_size;

word_and_count_t* find( const char* word ) // range checking ignored
{
  int i;

  for ( i = 0; i < table_size; ++i )
    if ( !strcmp( table[i].word, word ) )
      return table + i;

  strcpy( table[i].word, word );
  table[i].count = 0;

  ++table_size;

  return table + i;
}

void display()
{
  for ( int i = 0; i < table_size; ++i )
    printf( "%s - %d\n", table[i].word, table[i].count );
}

int main()
{
  //
  char s[] = "The greatness of a man is not in how much wealth he acquires, but in his integrity and his ability to affect those around him positively.";

  //
  for ( char* word = strtok( s, " ,." ); word; word = strtok( 0, " ,." ) )
    find( word )->count++;

  //
  display();

  return 0;
}

Answer 2

我认为主要的问题是您没有提供句子来获得这些单词。

char s[2222] = "Enter here the sentence you want to check.";