使用Javascript正则表达式从字符串的末尾删除int和float

Question

I found an answer in this question that is almost perfect but I need a slight tweak. I've read the basics of regex and I'm using https://regex101.com/ but I can't figure it out.

Using "string".replace(/\\d+$/, '') I can remove any numbers from the end of the string. However I also need to remove any numbers that have a format with a decimal like #.# or ##.# as well as whole numbers, but only when they appear at the end of the string. From regex101 I have found that the $ is for the end of the string.

I can use .replace(/\\d+([.]\\d+)?/g) to remove numbers and floats but it removes them from the entire string, not just when they appear at the end, and I can't work out where to put the $ as I don't really understand regex yet and can't get it to work.

It seems such a small and stupid problem but I'd appreciate the help.

Thanks

Answer 1

You may use

.replace(/\d+(?:\.\d+)?$/, '')

The pattern matches

• \\d+ - one or more digits
• (?:\\.\\d+)? - a non-capturing group (the ?: makes it non-capturing, that is, you cannot access the value captured by this group) that matches an optional sequence of a . and then 1+ digits
• $ - end of string.

To also remove any 0+ whitespaces before the number, add \\s* (where \\s matches any whitespace and * quantifier makes the regex engine match (consecutively) 0 or more of the characters matched with this pattern) at the pattern start.

See the regex demo .