如何抓取内联 css？

Question

I am using simple_html_dom script for getting information from a site.

I am trying to scrape an element that carrying the display: none property.

Here's the element:

<label data-product-attribute-value="1307" class="form-label" for="attribute_1307" style="display: none;">This is the title</label>

How can I identify that this tag carries inline CSS display: none;?

Here's my code:

$html  = get_html_data($url);
foreach ($html->find('.form-label') as $links) {
   echo $links->outertext;
}

$links->outertext is giving me only this:

<label data-product-attribute-value="1307" class="form-label" for="attribute_1307">This is the title</label>

You can see that, it's not including the style property while scraping.

So how can I get the inline CSS property? If I have to use a different library, please suggest.

Answer 1

You can get style using ->style . Try this:

foreach ($html->find('.form-label') as $links) {
   echo ($links->style); //op : display: none;
}

Answer 2

Doable for me as expected:

<?php
$html = <<< HTML
<label data-product-attribute-value="1307" class="form-label" for="attribute_1307" style="display: none;">
This is the title
</label>
HTML;

$dom = new DOMDocument;
$dom->loadHTML($html);
echo (   $label->hasAttribute('style')
      && preg_match('/display:\s*none/', $label->getAttribute('style')) ) ?
    "display set to 'none'" : "display NOT set to 'none'";

The output obviously is:

display set to 'none'