创建带有用户提示的输入的列表？

Question

I'm a beginner and taking an intro Python course. The first part of my lab assignment asks me to create a list with numbers entered by the user. I'm a little confused. I read some other posts here that suggest using "a = [int(x) for x in input().split()]" but I'm not sure how to use it or why, for that matter. The code I wrote before based on the things I've read in my textbook is the following:

 while True: 
  num = int(input('Input a score (-99 terminates): ')) 
   if num == -99: 
   break

Here's the problem from the professor:

Your first task here is to input score values to a list called scores and you will do this with a while loop. That is, prompt user to enter value for scores (integers) and keep on doing this until user enters the value of -99. Each time you enter a value you will add the score entered to list scores. The terminating value of -99 is not added to the list Hence the list scores should be initialized as an empty list first using the statement: scores = [] Once you finish enter the values for the list, define and called a find called print_scores() that will accept the list and then print each value in the list in one line separate by space. You should use a for-loop to print the values of the list.

Answer 1

I think this will do the job:

def print_scores(scores):
 for score in scores:
  print(str(score), end = " ")
 print("\n")

scores = []
while True:
 num = int(input('Input a score (-99 terminates)'))
 if num == -99:
  break
 scores.append(num)
print_scores(scores)

scores = [] creates an empty array and scores.append() adds the element to the list.

print() will take end = ' ' so that it separates each result with a space instead of a newline ( \\n' ) all while conforming to the requirement to use a loop for in the assignment. str(score) ensures the integer is seen as a string, but it's superfluous here.

This is actually not an elegant way to print the scores, but the teacher probably wanted to not rush things.

Answer 2

So yeah, you want to continually loop a scan, asking for input, and check the input every time. If it's -99, then break. If its not, append it to the list. Then pass that to the print function

def print_list(l):
    for num in l:
        print(num, ' ', end='')
l = []
while True:
    s = scan("enter some number (-99 to quit)")
    if s == "-99":
        break
    l.append(int(s))

print_list(l)

the print(num, ' ', end='') is saying "print num, a space, and not a newline"