子节点的Python / XML数量

Question

what I want to get from below xml file is: if number of <broader> nodes inside <term> node > 1 AND any of these <broader> node's value is equal to <id> node's value THEN print <value> node text.

            <results>
            <term>
                <altLabel>
                    <value>Label1</value>
                </altLabel>
                <broader>11</broader>
                <id>1</id>
            </term>
            <term>
                <altLabel>
                    <value>Label2</value>
                </altLabel>
                <broader>22</broader>
                <broader>2</broader>
                <id>2</id>
            </term>
            <term>
                <altLabel>
                    <value>Label3</value>
                </altLabel>
                <broader>3</broader>
                <broader>33</broader>
                <id>3</id>
            </term>
            <term>
                <altLabel>
                    <value>Label4</value>
                </altLabel>
                <broader>44</broader>
                <broader>44</broader>
                <id>4</id>
            </term>
        </results>

So that for above XML I suppose to get:

Label2
Label3

NOTE: number of child nodes inside <term> node may vary. This is just a sample xml, so that I'm not interested in pointing on any specific element of table.

Answer 1

What you can do, using BeautifulSoup is to loop over all term tags, and check if their id text is equal to any of their broader texts:

from bs4 import BeautifulSoup
soup = BeautifulSoup(doc, 'lxml') #  doc is your string
termList = soup.findAll("term")
for term in termList:
    if len(term.findAll("broader")) > 1:
        for broader in term.findAll("broader"):
            if term.id.text == broader.text:
                print(term.value.text)

Will print:

Label2
Label3

Answer 2

using builtin xml module, the sytax is quite similar to beautifulsoup :)

Replace path_to_xml to your xml file path

from xml.etree import cElementTree as ET
xml_dat = ET.parse(path_to_xml).getroot()
for term in xml_dat.iter('term'):
    broaders = term.findall('broader')
    if len(broaders) > 1:
        for broader in broaders:
            if term.find('id').text == broader.text:
                print(term.find('altLabel').find('value').text)