从2个表中获取数据并在一个查询中创建一个表

Question

I have two MySQL tables:

offers:

  id   |   rid   |    name 
------------------------------
  1    |  1234   |    mary

  2    |  1235   |    john

  3    |  5342   |    liam

And

geo_in_off:

offer_id   |   geo_id   
------------------------------
   1       |  1234  
   2       |  1235   
   3       |  5342   

I need to make a table on my website looging like:

1(number) | 1234(rid) | name(name) | 1(geo_id)

But I got MySQL troubles.

My code is:

require('../config.php');
echo "<table class=\"offer-table\">";
echo "<tr><th id=\"off_col_num\">№</th><th id=\"off_col_id\">offer ID</th><th id=\"off_col_name\">Название</th><th id=\"off_col_geo\">Geo</th></tr>";
$i = 1;
$sql ="SELECT * FROM `offers` ORDER BY `rid` JOIN geo_in_off ON geo_in_off.id = offers.id"; 
$result = mysql_query($sql) or die(mysql_error()); 

while ($row=mysql_fetch_assoc($result)) {
    echo "<tr><td>" . $i . "</td><td>" . $row['rid'] . "</td><td>" . 
    $row['name'] . "</td><td>" .$i . "</td></tr>"  ;
    $i++;
}

echo "</table>";    

I've got problems with MySQL synaxis and the logic how to get the data from 2 tables and give the result in one "while loop".

So I need to join 2 queries in one:

$sql ="SELECT * FROM `offers` ORDER BY `rid`";
$sql ="SELECT `geo_id` FROM `geo_in_off` WHERE `offer_id` = '$each_offer_id_from_offers'";

And optional but not necessary:

$sql ="SELECT `name` FROM `geo` WHERE `id` = '$geo_id_got_from_table_geo_in_off'";

And get a table where I get the offer id, the offer name and the offer geo.

Answer 1

Try this query, it does help you (full join query)

SELECT offers.*, geo_in_off.geo_id FROM offers,
geo_in_off WHERE offers.id=geo_in_off.offer_id

Answer 2

Change

$sql ="SELECT * FROM `offers` ORDER BY `rid` JOIN geo_in_off ON geo_in_off.id = offers.id";

To

$sql ="SELECT * FROM `offers` JOIN `geo_in_off` ON `geo_in_off`.`offer_id` = `offers`.`id` ORDER BY `offers`.`rid`";

1) ORDER BY order is wrong in your query

SELECT column1, column2, ...

FROM table_name
ORDER BY column1, column2, ... ASC|DESC;

2) Instead of geo_in_off.id = offers.id use geo_in_off.offer_id = offers.id

Answer 3

Try this query:

$sql = 'SELECT of.id, of.rid, of.name, geo.id 
FROM of.offers 
INNER JOIN of.id = geo.offer_id 
WHERE offer_id = \''.$each_offer_id_from_offers.'\' order by of.rid'