我可以在Codeigniter中的函数之间传递数据吗？

Question

im loading a simple form as a subview, i need to pass the data to the next function but when I use $this->data i get a blank page. here is my controller:

 <?php
defined('BASEPATH') OR exit('No direct script access allowed');

class Search extends Admin_Controller {


    function __construct()
    {
        parent::__construct();
        $this->load->library('form_validation');
        $this->load->helper('form');
        $this->load->model('search_model');

    }
    function index()
    {

        $this->data['subview'] = ('../views/user/search_form');
        $this->load->view('../views/_layout_admin', $this->data);
    }
    function execute_search()
    {
        // Retrieve the posted search term.
        $search_term = $this->input->post('search');

        // Use a model to retrieve the results.
        $data['results'] = $this->search_model->get_results($search_term);

        // Pass the results to the view.
        $this->data['subview'] = ('../views/user/search_results');
        $this->load->view('../views/user/search_results', $this->data);

    }
    }

Any help/ideas? much apreciated

Answer 1

您还可以通过在主视图中执行以下操作来加载子视图：

<?php $this->load->view('user/search_form'); ?>

Answer 2

Replacing your controller by this code:

 <?php
defined('BASEPATH') OR exit('No direct script access allowed');

class Search extends Admin_Controller {


    function __construct()
    {
        parent::__construct();
        $this->load->library('form_validation');
        $this->load->helper('form');
        $this->load->model('search_model');

    }
    function index()
    {

        $data['subview'] = ('../views/user/search_form');
        $this->load->view('layout_admin', $data);
    }
    function execute_search()
    {
        // Retrieve the posted search term.
        $search_term = $this->input->post('search');

        // Use a model to retrieve the results.
        $data['results'] = $this->search_model->get_results($search_term);

        // Pass the results to the view.
        $data['subview'] = ('../views/user/search_results');
        $this->load->view('search_results', $data);

    }
    }