SQL查询以查找表中包含所有元音的所有值。

Question

This is the first week I have ever worked with SQL. It's rather straightforward and has been fairly easy to pick up.

I had to write a query to find all countries that contain all the vowels ('aeiou') and no white spaces in their name. The only country that fit this criteria was Mozambique.

SELECT
  name 
FROM 
  world 
WHERE 
  name LIKE '%a%' AND name LIKE '%e%' AND name LIKE '%i%' AND name LIKE       
 '%o%' AND name LIKE '%u%' AND name NOT LIKE '% %'

The above query worked. I wanted to now if there was a way to shorten this, so I could use one LIKE statement and check if the word contained all of those letters in it's name without order mattering.

Answer 1

In PostgreSQL you can do that like so:

    SELECT w.name
    FROM world AS w
    WHERE w.name SIMILAR TO '%(a|e|i|o|u)%' 
      AND w.name NOT SIMILAR TO '% %';

Answer 2

There are other options but nothing much shorter. A couple examples below.

...WHERE LOCATE('a',name) AND LOCATE('e',name) ...

...WHERE name REGEXP 'a' AND name REGEXP 'e' ...

( mysql 5.7 pattern matching documentation may help too)