使用Ajax和PHP将数据发送到MySQL，但没有任何反应

Question

I want to send a simple data, like name, code, date... etc to my Database, I got the data using JavaScript, and sent it to my PHP file using Ajax, but nothing happens and I don't know what's happening, but Ajax do nothing!! So, please can anyone review the code, and tell what's going on.. thanks

PS my script in the END of my HTML file, right before the ending tag.

 <script type="text/javascript"> debugger; window.onload = function() { var platform = $("input:text[id=platform]").val(); var source = $("input:text[id=source]").val(); var code = $("input:text[id=code]").val(); var thedate = $("input:text[id=date]").val(); var payment_type = $("input:text[id=payment_type]").val(); var change_for = $("input:text[id=change_for]").val(); var order_comment = $("#order_comment").val(); var decline_reason = $("input:text[id=decline_reason]").val(); var order_reference_by_vendor = $("input:text[id=order_reference_by_vendor]").val(); var deliveryprovider_title = $("input:text[id=deliveryprovider_title]").val(); var social_reason = $("input:text[id=social_reason]").val(); var government_identification = $("input:text[id=government_identification]").val(); if(platform == ""){platform = "NULL"} if(source == ""){source = "NULL"} if(code == ""){code = "NULL"} if(thedate == ""){thedate = "NULL"} if(payment_type == ""){payment_type = "NULL"} if(change_for == ""){change_for = "NULL"} if(order_comment == ""){order_comment = "NULL"} if(decline_reason == ""){decline_reason = "NULL"} if(order_reference_by_vendor == ""){order_reference_by_vendor = "NULL"} if(deliveryprovider_title == ""){deliveryprovider_title = "NULL"} if(social_reason == ""){social_reason = "NULL"} if(government_identification == ""){government_identification = "NULL"} alert ("before ajax"); $.ajax({ type:"post", url:"savedata.php", data:{"platform": platform, "source": source, "code": code, "thedate": thedate, "payment_type": payment_type, "change_for": change_for, "order_comment": order_comment, "decline_reason": decline_reason, "order_reference_by_vendor": order_reference_by_vendor, "deliveryprovider_title": deliveryprovider_title, "social_reason": social_reason, "government_identification": government_identification}, success: function(msg){ alert("Success Insert data"); } }); alert ("after ajax"); } </script> 

and here's the PHP code

 <?php function db_connect() { $servername = "localhost"; $username = "root"; $password = ""; $dbname = "integrationdb"; @mysql_connect($servername,$username,$password) or die ("error in host connection"); @mysql_select_db($dbname) or die("error in db connection"); } db_connect(); $platform = $_POST['platform']; $source = $_POST['source']; $code = $_POST['code']; $thedate = $_POST['thedate']; $payment_type = $_POST['payment_type']; $change_for = $_POST['change_for']; $order_comment = $_POST['order_comment']; $decline_reason = $_POST['decline_reason']; $order_reference_by_vendor = $_POST['order_reference_by_vendor']; $deliveryprovider_title = $_POST['deliveryprovider_title']; $social_reason = $_POST['social_reason']; $government_identification = $_POST['government_identification']; $qry = "INSERT INTO orderinformation VALUES ('$platform','$source','$code','$thedate','$payment_type','$change_for','$order_comment','$decline_reason','$order_reference_by_vendor','$deliveryprovider_title','$social_reason','$government_identification')"; $result=mysql_query($qry); if(isset($result)) { echo "YES"; } else { echo "NO"; } ?> 

• EDIT Excuse me if I'm asking... will it do difference if I use ( ' ) instead of ( " ) in JSON??!

Answer 1

尝试通过chrome工具栏查看网络，它可以帮助您跟踪请求，读取其标头并检查可能包含错误消息的响应数据