如何将数字格式化为N个小数，其中N是随机的

Question

I want to encrypt a number up to N decimals. The process I use sometimes generates less decimals than N so I need to pad the rest with zeroes to the left. I tried this:

N = 5 # The number of decimals needed for encryption

encrypted = '%0Nd' % (x) # here x is a number used to encrypte the original number 

but N in encrypted should be a number priory determined.

Answer 1

encrypted = '{:0{width}d}'.format(x, width=N)

Answer 2

Python 3.6 solution with format strings:

encrypted = f'{d:0{N}}'

For example,

>>> d = 5
>>> N = 3
>>> f'{d:0{width}}'
005