[英]Return object from function to which JSON is passed
Dears, 亲爱的,
I have a function, to which i input JSON data 我有一个函数,我向其输入JSON数据
function getTotals(users){
users = data;
allUsers = users.length;
active = 0;
women = 0;
men = 0;
lastActive = 0;
for (elm in users){
if (users[elm].active){
active++;
if (users[elm].gender == "Female"){
women++;
} else if (users[elm].gender == "Male") {
men++;
} else if (users[elm].last_login){
var lastLogin = new Date (users[elm].last_login);
var lastMonths = lastLogin.getMonth()-6;
var lastYears = lastLogin.getFullYear();
//console.log(lastYears);
if (lastMonths <6 && lastMonths > -6 && lastYears >= lastLogin.getFullYear()-1){
lastActive++;
}
}
}
}
return {allUsers : allUsers, active : active, women : women, men : men, lastActive : lastActive};}
but i cannot display the values, when i do following: 但是当我执行以下操作时,我无法显示这些值:
var listOfUsers = document.createElement('p');
listOfUsers.textContent = "Liczba wszystkich użytkowników: "+allUsers;
document.querySelector("#row1 > div").appendChild(listOfUsers);
var listOfActive = document.createElement('p');
listOfActive.textContent = "Liczba aktywnych użytkowników: "+active;
document.querySelector("#row2 > div").appendChild(listOfActive);
var listOfWomen = document.createElement('p');
listOfWomen.textContent = "Liczba aktywnych kobiet: "+women;
document.querySelector("#row3 > div").appendChild(listOfWomen);
var listOfMen = document.createElement('p');
listOfMen.textContent = "Liczba aktywnych mężczyzn: "+men;
document.querySelector("#row4 > div").appendChild(listOfMen);
var listOfLastActv = document.createElement('p');
listOfLastActv.textContent = "Liczba aktywnych (ost 6 mcy): "+lastActive;
document.querySelector("#row5 > div").appendChild(listOfLastActv);
When i do following (found here in other questions): 当我执行以下操作(在其他问题中找到此处)时:
var getTotalUsers = new getTotal();
var allUsers = getTotalUsers.allUsers;
var active = getTotalUsers.active;
var women = getTotalUsers.women;
var men = getTotalUsers.men;
var lastActive = getTotalUsers.lastActive;
I get undefined as a result. 结果我不确定。 I do not know how to fix this issue, as in next part of js, i will need to display list of active users.
我不知道如何解决此问题,因为在js的下一部分中,我将需要显示活动用户列表。
new Promise()
returns results asynchronously. new Promise()
异步返回结果。 You can either chain .then()
or use async/await
to get expected result 您可以链接
.then()
或使用async/await
获得预期的结果
function httpGet() { return new Promise(function(resolve) { setTimeout(function() { resolve([{a:1}, {b:2}, {c:3}]) }, Math.floor(Math.random() * 1200)) }) } async function getTotals() { const users = await httpGet(); console.log(users); } getTotals();
function httpGet() { return new Promise(function(resolve) { setTimeout(function() { resolve([{a:1}, {b:2}, {c:3}]) }, Math.floor(Math.random() * 1200)) }) } function getTotals() { const data = httpGet(); data.then(function(users) { console.log(users) }) .catch(function(err) { console.log(err) }) } getTotals();
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