复制curl命令python 3 urllib请求API

Question

This problem is kind of driving me crazy. I'm doing a very simple python 3 script to manage an API in a public website. I am able to do it with curl, but not in pyhton. Can't use either requests library or curl in my real environment, just for tests

This is working:

curl -d "credential_0=XXXX&credential_1=XXXXXX" -c cookiefile.txt https://XXXXXXXXXXXXXXX/LOGIN

curl -d 'json={"devices" : ["00:1A:1E:29:73:B2","00:1A:1E:29:73:B2"]}' -b cookiefile.txt -v https://XXXXXXXXX/api-path --trace-ascii /dev/stdout

and we can see this in the curl debug:

Send header, 298 bytes (0x12a)

0000: POST /api-path HTTP/1.1

0034: Host: XXXXXXXXXXXXXXXX

0056: User-Agent: curl/7.47.0

006f: Accept: /

007c: Cookie: csrf_token=751b6bd9-0290-496b-820e-XXXXXXXX; session 00bc: =XXXXXX-6d29-4cf9-8907-XXXXXXXXXXXX

00e3: Content-Length: 60

00f7: Content-Type: application/x-www-form-urlencoded

0128: => Send data, 60 bytes (0x3c)

0000: json={"devices" : ["00:1A:1E:29:73:B2","00:1A:1E:29:73:B2"]} == Info: upload completely sent off: 60 out of 60 bytes

This is the python code to replicate the second request, which is the problematic one

string_query={"devices" : [ "34:FC:B9:CE:14:7E","00:1A:1E:29:73:B2" ]}
jsonbody_url=urllib.parse.urlencode(string_query)
jsonbody_url=jsonbody_url.encode("utf-8")

req=urllib.request.Request(url,data=jsonbody_url,headers={"Cookie" : 
cookie,"Content-Type": "application/x-www-form-urlencoded","User-
Agent":"curl/7.47.0","charset":"UTF-8","Content-
length":len(jsonbody_url),
"Connection": "Keep-Alive"},method='POST')

And the server is completely ignoring the Json content. Everything else is working, login and other url parameters from the same API

Any ideas?

Answer 1

Try this:

import requests

string_query={"devices" : [ "34:FC:B9:CE:14:7E","00:1A:1E:29:73:B2" ]}
headers={
  "Cookie" : cookie,
  "Content-Type": "application/x-www-form-urlencoded",
  "User-Agent":"curl/7.47.0",
  "charset":"UTF-8",
  "Connection": "Keep-Alive"
}
response = requests.post(url,data=string_query,headers=headers)
print(response.content)