使用 XMLUnit 2.X 比较 xml 文件时忽略特定节点的特定属性

Question

I have two XML files:我有两个 XML 文件：

<!------------------------File1--------------------------------->
    <note id="ignoreThisAttribute_1">
      <to>Experts</to>
      <from>Matrix</from>
      <heading id="dontIgnoreThisAttribute_1">Reminder</heading>
      <body>Help me with this problem</body>
    </note>

<!------------------------File2--------------------------------->
    <note id="ignoreThisAttribute_2">
      <to>Experts</to>
      <from>Matrix</from>
      <heading id="dontIgnoreThisAttribute_2">Reminder</heading>
      <body>Help me with this problem</body>
    </note>

I have to ignore the attribute: id of Node: note while comparing these two files.在比较这两个文件时，我必须忽略属性：节点的id ： note 。

I am using DiffBuilder :我正在使用DiffBuilder ：

Diff documentDiff = DiffBuilder.compare(srcFile).withTest(destFile).build()

Most online solutions suggested implementing DifferenceEvaluator :大多数在线解决方案建议实施DifferenceEvaluator ：

Tried that as well, but this ignores all nodes with attribute id, whereas I want to ignore an attribute from a specific node:也尝试过，但这会忽略具有属性 id 的所有节点，而我想忽略来自特定节点的属性：

public class IgnoreAttributeDifferenceEvaluator implements DifferenceEvaluator {
        private String attributeName;
        public IgnoreAttributeDifferenceEvaluator(String attributeName) {
            this.attributeName = attributeName;
        }

        @Override
        public ComparisonResult evaluate(Comparison comparison, ComparisonResult outcome) {
            if (outcome == ComparisonResult.EQUAL)
                return outcome;
            final Node controlNode = comparison.getControlDetails().getTarget();


            System.out.println(controlNode.getNodeName());
            if (controlNode instanceof Attr) {
                Attr attr = (Attr) controlNode;
                if (attr.getName().equals(attributeName)) {
                    return ComparisonResult.EQUAL;
                }
            }
            return outcome;
        }
    }

Calling method in my Test class:在我的测试类中调用方法：

final Diff documentDiff = DiffBuilder.compare(src).withTest(dest)
.withDifferenceEvaluator(new IgnoreAttributeDifferenceEvaluator("id"))
.build();

Can someone suggest me a way I can achieve this using XMLUnit 2.x New to XMLUnit so please help accordingly.有人可以建议我使用 XMLUnit 2.x 来实现这一点新的 XMLUnit，所以请相应地提供帮助。

Thanks in advance.提前致谢。

Answer 1

You could use a DifferenceEvaluator if you really wanted to.如果您真的愿意，您可以使用DifferenceEvaluator 。 All you'd have to do was testing the name of the Attr 's "owner element"'s name in addition to the name of the attribute itself.除了属性本身的名称之外，您所要做的就是测试Attr的“所有者元素”的名称。

But XMLUnit 2.x offers a different solution to this: AttributeFilter .但是 XMLUnit 2.x 对此提供了不同的解决方案： AttributeFilter 。 The code won't be that different from the DifferenceEvaluator you've already got, but you won't be mixing concerns.该代码DifferenceEvaluator您已经获得的DifferenceEvaluator没有太大区别，但您不会混淆关注点。

class IgnoreNoteId implements Predicate<Attr> {

    public boolean test(Attr attr) {
        return !("note".equals(attr.getOwnerElement().getNodeName())
            && "id".equals(attr.getNodeName()));
    }
}

or even shorter with a lambda in withAttributeFilter when using Java8.甚至在使用 Java8 时在withAttributeFilter使用 lambda 更短。

使用 XMLUnit 2.X 比较 xml 文件时忽略特定节点的特定属性

问题描述

1 个解决方案

解决方案1
4 已采纳 2017-07-26 06:49:23

使用 XMLUnit 2.X 比较 xml 文件时忽略特定节点的特定属性

问题描述

1 个解决方案

解决方案1 4 已采纳 2017-07-26 06:49:23

解决方案1
4 已采纳 2017-07-26 06:49:23