bash-如何查找和压缩包含字符串的文件？

Question

I want to zip all files contain string '12345' to file mylog.zip. Using grep -li can find the file and use this command but it does not zip the files.

grep -l 12345  *  |  zip  mylog.zip; 

I try command

grep -l 12345  *

It found the files. Issue is how to pass this to zip.

Answer 1

find -name "*12345*" -type f -print | zip name.zip -@

要么

find -name "*12345*" -type f -exec zip name.zip {} +

Answer 2

Another using bash for loop. Add proper quoting around variables if needed. In this example I grep for a in a bunch of files:

$ for f in *.txt; do grep -q a $f; if [ $? -eq 0 ]; then zip my.zip $f ; fi ; done
  adding: test1.txt (stored 0%)
  adding: test3.txt (stored 0%)

Written open:

for f in *.txt
do 
    grep -l a $f
    if [ $? -eq 0 ]
    then 
        zip my.zip $f
    fi
done