Shell脚本查找命令，用于将文件名与一个或另一个单词匹配

Question

I am looking for a command for bash shell script to find the list of files in a directory whose names start with either WordA or WordB and end with digits.

I have this command with WordA and duplicating the same code with WordB .

find /log/ -name 'WordA*[[:digit:]]'

I tried putting Or condition in various formats such as (WordA|WordB) , [WordA|WordB] , [(WordA)|(WordB)] , [(WordA)||(WordB)] to match WordA or WordB followed by digits.

None of them worked.

Answer 1

You need to use the -regextype supported in find command, in the case used the posix-extended type and do

-regextype type
      Changes the regular expression syntax understood by -regex and -iregex 
      tests which occur later on the command line.  Currently-implemented  
      types  are  emacs (this is the default), posix-awk, posix-basic, 
      posix-egrep and posix-extended.

So your command should be

find /log/ -regextype posix-extended -regex './(WordA|WordB)([[:digit:]]+)$'

Answer 2

In the find man page, under header Expressions, you'll find (no pun intended) the following

Operators

Operators join together the other items within the expression. They include for example -o (meaning logical OR) and -a (meaning logical AND). Where an operator is missing, -a is assumed.

Thus the answer to your problem appears to be

 find /log/ -name 'WordA*[[:digit:]]' -o 'WordB*[[:digit:]]'