[英]How to get CSS class name value part within the property
Is there any option to get the class name value within property. 是否有任何选项可以在属性中获取类名称值。 Here, I need 12.
在这里,我需要12。
.grid-12{ grid-template-columns: repeat(12, 1fr); }
Thanks in advance. 提前致谢。
Using something like that 使用类似的东西
document.querySelector('div').style['grid-template-columns']
you can obviously get the value and then parse it but in my eyes that looks kinda ugly. document.querySelector('div').style['grid-template-columns']
您显然可以获取该值,然后对其进行解析,但是在我看来这看起来很丑。
The best you can to do is to use a css parser to transform the css into a AST tree and iterate over it. 最好的办法是使用CSS解析器将CSS转换为AST树并对其进行迭代。 That of course has its own trade-offs and usually doesn't worth to do it in the frontend, its not even 100% sure that the parser will give you that value.
当然,这是有其自身取舍的,通常不值得在前端进行,甚至不能100%保证解析器会为您提供该值。 eg I see that your snippet in a parser is transform to the following AST tree
例如,我看到您在解析器中的代码段已转换为以下AST树
{
"parentStyleSheet": null,
"cssRules": [
{
"parentRule": null,
"parentStyleSheet": "[Circular ~]",
"selectorText": ".grid-12",
"style": {
"0": "grid-template-columns",
"length": 1,
"parentRule": "[Circular ~.cssRules.0]",
"_importants": {
"grid-template-columns": ""
},
"__starts": 8,
"grid-template-columns": "repeat(12, 1fr)"
},
"__starts": 0,
"__ends": 55
}
]
}
So again, you have to manually extract the 12
再次,您必须手动提取
12
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