如何通过逻辑运算符（和或）在Java中拆分字符串，但是如果它们出现在引号中则不考虑它们？

Question

I have a string that I need to split by logical operators "and", "or" (case insensitive). However, I should not be considering these logical operator patterns if they appear in quotes, single or double. A sample pattern:

contains(field1,'sample') or contains(field2,'aaandbb') AND (field3 gt 5000)

The output of the split I am trying to achieve:

contains(field1,'sample')

contains(field2,'aaandbb')

(field3 gt 5000)}

Note: Please ignore the brackets.

My code:

String soregex1="\\s+(?i)(and)|(or)\\s+";
    String[] splitStr = so1.split(soregex1);
    for(String str1:splitStr) {
        System.out.println(str1);
    }

All good except when pattern, that is, conditional operators, start appearing as values to string conditions. For example:

contains(field1,'sam or ple') or contains(field2,'aa and bb') AND (field3 gt 5000)

The output for above string with my code is:

contains(field1,'sam

ple')

contains(field2,'aa

bb')

(field3 gt 5000)

instead of

contains(field1,'sam or ple')

contains(field2,'aa and bb')

(field3 gt 5000)

I also need to factor in escaped singleor double quotes. Appreciate any suggestions on how to avoid considering pattern matches that appear in single quotes or double quotes.

Answer 1

have you tried this:

(\\)\\s*(AND))|(\\)\\s*(OR))

demo

Answer 2

This is a bit wild and crazy, but why not match the tokens themselves instead of splitting on the delimiter. (I'm assuming the (...) is mandatory. Case insensitive match)

\\w*\\(.*?\\)(?=\\s*(?:and|or|$))

( demo )