具有三元运算符语法的JavaScript Prime Checker函数

Question

How can I refactor the following using the ternary operator syntax instead?

let divisor = 2;
let isPrime = (num) => {
        if (num % divisor === 0) return false;
        else divisor++;
        return true;
};

console.log(`prime is ${isPrime(83)}`);

Answer 1

You can use conditional operator with comma operator following : at exp2

 let divisor = 2; let isPrime = num => num % divisor === 0 ? false : (++divisor, true); console.log(`prime is ${isPrime(83)}`); 

Answer 2

You can increment the number and convert it to a Boolean, because numbers that are not 0 will be converted to true

(num) => num % divisor ? // > 0 == true : 0 == false
    !!(++divisor) // increment and convert to boolean
    : 
    false

 let divisor = 2; const isPrime = (num) => num % divisor ? !!(++divisor) : false; console.log(`prime is ${isPrime(83)}`);