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在PHP 7.0中编码多维数组不起作用(json_encode)

[英]encoding multidimensional array in PHP 7.0 doesn't work (json_encode)

I have a problem with getting JSON data from mysql phpmyadmin(Version 4.0) table, I have tried PDO and mysql_connect. 我从mysql phpmyadmin(Version 4.0)表获取JSON数据时遇到问题,我尝试了PDO和mysql_connect。

My idea: mysql--> PHP--> echo json 我的想法是:mysql-> PHP-> echo json

The connection to my server works and the SQL statement works perfectly. 与服务器的连接正常,SQL语句正常运行。 I have tested it. 我已经测试过了 But the "json_encode"(and some others) of the JSON itself is not possible. 但是JSON本身的“ json_encode”(以及其他一些符号)是不可能的。 The json array is not builted. json数组未构建。

Are there settings in PhpMyAdmin which I have to pay attention to? 我必须注意PhpMyAdmin中的设置吗?

PDO: PDO:

      $query = $pdo->prepare('SELECT p.*, count(r.rate) AS rates, avg(r.rate) AS average from plugins p left join rate r on p.title = r.title group by p.title');
        $query->execute();
        $row = $query->fetchAll();
        // send the data encoded as JSON
        $json = json_encode($row, JSON_UNESCAPED_UNICODE);
echo $json;
       print_r($row);
        exit;

Result is: 结果是:

Array ( [0] => Array ( [id] => 153 [0] => 153 [title] =>

Where am I going wrong? 我要去哪里错了? I updated my server to PHP 7.0 and now the code doesn't work. 将服务器更新为PHP 7.0 ,现在代码不起作用。 Before the update all is working perfectly and there was a long json array(how it should be) 在更新之前,一切工作正常,并且有一个很长的json数组(应该如何)

How it should be 应该如何

{{"id":"1","title":"ExmapleTitle"....},{"id":"2","title":"ExmapleTitle2"....}...} 

You must call execute() 您必须调用execute()

    <?php

    $pdo = new PDO('mysql:host=xxxxx;dbname=xxxxx', 'xxxxxx', 'xxxxxx');

    $statement=$pdo->prepare("SELECT p.*, count(r.rate) AS rates, avg(r.rate) AS average from plugins p left join rate r on p.title = r.title group by p.title");

    $statement->execute(); // <<< --- You are missing this
    $data = $statement->fetchAll(PDO::FETCH_ASSOC);
    echo json_encode($data); //Echo: data ... voila

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