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通过值索引获取Guava Multimap的键

[英]Get key of Guava Multimap by index of value

Suppose this is my example data which are in Multimap collection: 假设这是我在Multimap集合中的示例数据:

x -> [1,2]
y -> [1,3]
z -> [4]

then I made a list of values which might be like this:(First column is index of values , second column is value) 然后我列出了一个可能像这样的值列表:(第一列是值的索引,第二列是值)

0 -> 1
1 -> 2
2 -> 1
3 -> 3
4 -> 4

My question is how to get paired key of a value by knowing index of that value. 我的问题是如何通过知道该值的索引来获取该值的配对键。 For example the key for index "2" , the key "y" must return. 例如,索引“ 2”的键,键“ y”必须返回。

If you want to do this one time, you can do simple loop over Multimap#entries() and maintain counter yourself, but: 如果您想一次执行此操作,则可以对Multimap#entries()进行简单循环并自己维护计数器,但是:

  1. order of iteration over various Mutlimap implementations could be different 各种Mutlimap实现的迭代顺序可能不同
  2. if main use case is access keys/values by index, you shouldn't use Multimap here at all, but maintain a list (probably List<Entry<String, Integer>> ). 如果主要用例是按索引访问键/值,那么您根本不应该在这里使用Multimap ,而应该维护一个列表(可能是List<Entry<String, Integer>> )。

If you really have to have multimap and it's immutable, you could use .entries().asList() view to achieve what I described above: 如果确实需要.entries().asList()并且它是不可变的,则可以使用.entries().asList()视图来实现我上面所述的内容:

//given
ImmutableListMultimap<String, Integer> multimap =
        ImmutableListMultimap.<String, Integer>builder()
                .putAll("x", 1, 2)
                .putAll("y", 1, 3)
                .putAll("z", 4)
                .build();
ImmutableList<Map.Entry<String, Integer>> entriesWithPosition =
        multimap.entries().asList();
//when
Map.Entry<String, Integer> foundEntry = entriesWithPosition.get(2);
//then
assertThat(foundEntry.getKey()).isEqualTo("y");

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