Linux和python中的高级文件处理

Question

I have a piece of code to make some changes in a file in Python. I wish to perform that action on multiple files of a folder. I wrote the following code to do that:

import re import os files = os.listdir("/home/intucell/tarfiles") for file in files: fp = open (file, 'r') for line in fp: print(line.replace ('4.0.0', '5.0.0')) f.close()

I want the code to run for multiple files in a folder called tarfiles. The names of these files have to be read from the listing of that folder. But, Linux does not read filenames containing spaces. I have about 100 files containing spaces in their names. How do I go about it?

Answer 1

Assuming that you have the list of files filelist you want to work on, you can simply use:

import re
for filename in filelist:
    fp = open (filename, 'r') 
    for line in fp: print(line.replace (' 4.0.0 ', ' 5.0.0 '))
         print(re.sub(r'\b4.0.0[^.]', '5.0.0 ', line))`

Or do you need to look for the files in the folder?

Answer 2

You can use a for loop for this one. Eg

import os
item_list = next(os.walk(your_directory_path))[1]
for i in item_list:
     fp = open (str(i), 'r')
     for line in fp: print(line.replace (' 4.0.0 ', ' 5.0.0 '))
         print(re.sub(r'\b4.0.0[^.]', '5.0.0 ', line))

I hope that will help

Answer 3

you can use os.listdir, suppose the multiple files you want to change are in folder which is stored in the path variable, then:

files = os.listdir(path)
for _file in files:
    fp = open (_file, 'r')
    for line in fp:
        print(line.replace (' 4.0.0 ', ' 5.0.0 '))
        print(re.sub(r'\b4.0.0[^.]', '5.0.0 ', line))

EDIT: also don't forget to import os