仅在SQL Server的表中从前一天恢复数据

Question

I need to retrieve data from a table that has date referenced only the previous day, I am trying to do with the query below but I am not getting:

SELECT 
    Log.ValorEntrada, Log.DataHoraEvento, Log.NumeroEntrada 
FROM 
    Log 
WHERE 
    Log.DataHoraEvento = (GETDATE()-1)

How can I get this result?

Answer 1

In SQL Server, GETDATE() has a time component. I would recommend:

WHERE Log.DataHoraEvento >= CAST(GETDATE()-1 as DATE) AND
      Log.DataHoraEvento < CAST(GETDATE() as DATE)

This condition is "sargable", meaning that an index can be used. The following also is:

WHERE CONVERT(DATE, Log.DataHoraEvento) >= CONVERT(DATE, GETDATE())

Almost all functions prevent the use of indexes, but conversion/casting to a date is an exception.

Finally, if you don't care about indexes, you can also write this as:

WHERE DATEDIFF(day, Log.DataHoraEvento, GETDATE()) = 1

DATEDIFF() with day as the first argument counts the number of "day" boundaries between the two date/times. Everything that happened yesterday has exactly one date boundary.

Answer 2

If DataHoraEvento is a DATETIME , its likely that it has the full time, hence GETDATE()-1 isn't getting any matches. You should search for a range like this:

SELECT L.ValorEntrada, L.DataHoraEvento, L.NumeroEntrada 
FROM dbo.[Log] L
WHERE L.DataHoraEvento >= CONVERT(DATE,DATEADD(DAY,-1,GETDATE()))
AND L.DataHoraEvento < CONVERT(DATE,GETDATE());

Answer 3

SELECT Log.ValorEntrada, Log.DataHoraEvento, Log.NumeroEntrada 
FROM   Log 
WHERE  Log.DataHoraEvento >= DATEADD(dd,DATEDIFF(dd,1,GETDATE()),0) 
AND    Log.DataHoraEvento < DATEADD(dd,DATEDIFF(dd,0,GETDATE()),0)

You should also use SYSDATETIME() (if you on SQL Server 2008+) instead of GETDATE() as this gives you datetime2(7) precision.

Answer 4

你可以试试这个：

MEMBER BETWEEN DATEADD(day, -2, GETDATE()) AND DATEADD(day, -1, GETDATE())