[英]How to select input element with Python Selenium
I just cannot find working way to select this element, tried by CSS and xpath, but nothing works. 我只是找不到通过CSS和xpath尝试选择此元素的工作方法,但是没有任何效果。
<input type="submit" value="Submit">
This does not work: 这不起作用:
driver.find_element_by_xpath("//*[@id='theform']/div[2]/input").click()
driver.find_element_by_css_selector(".submit[value='Submit']").click()
This does not work: 这不起作用:
driver.find_element_by_xpath("//*[@id='theform']/div[2]/input").click() driver.find_element_by_css_selector(".submit[value='Submit']").click() driver.find_element_by_xpath(“ // * [@ id ='theform'] / div [2] / input”)。click()driver.find_element_by_css_selector(“。submit [value ='Submit']”)。click()
The first invocation likely does not work because the input
descendant node is most likely too vague and ambiguous. 第一次调用可能无法工作,因为input
后代节点很可能过于模糊和模棱两可。
The second invocation doesn't work because .submit[value='Submit']
is searching for (in english) 第二次调用无效,因为.submit[value='Submit']
正在搜索(英文)
Any element that has
class~="submit"
ANDvalue="Submit"
任何具有class~="submit"
ANDvalue="Submit"
元素
The value
attribute matches, but not the class selector. value
属性匹配,但类选择器不匹配。
You could find that element with a quick CSS selector: 您可以使用快速的CSS选择器找到该元素:
driver.find_element_by_css_selector("input[type='submit']")
See Effective CSS Selectors to see how to formulate good CSS selectors, and why this selector above would work. 请参阅有效的CSS选择器,以了解如何制定良好的CSS选择器以及为什么该选择器可以正常工作。
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